Loading Data In a TextBox Thru Ajax

PHP
1

In my form I dynamically created a textbox, therefore an array of textbox. If a user select an option into a combo box, data will be retrieved in the database an will be displayed on the dynamically created textboxes.

My problem is, how am I be able to display the data into these array of textbox using AJAX, can anyone help me. Thanks in advance.

2

I think I vaguely understand what you’re saying but you’re not showing any source code :rolleyes:

If you can show us that, it might give us a clearer picture.

3

Here’s my code in creating dynamic textbox


<?php
        $query = "SELECT details FROM award WHERE id=$awardid";
        $result = mysql_query($query);
        $award = mysql_fetch_array($result);
      ?>
      <div id="heading">::CRITERIA FOR <?php echo $award['details']; ?>::</div>
      <div id="entrybody">
      <div class="entryheading">&nbsp;</div>
        <form method="post">
            <label style="width: 200px; float: left; padding-left: 5px; text-align: right; margin-top: 5px;">Contestant:</label>
            <select name="cboContestant" style="font-weight: bold;" >
              <option value=""></option>
              <?php
                $query = "SELECT id, contestantno, contestantname FROM contestants WHERE competitionid='$_SESSION[competitionid]'";
                $result = mysql_query($query);
                while($contestant = mysql_fetch_array($result))
                {
                  echo "<option value='$contestant[id]' ";
                        if($_POST['cboContestant']==$contestant['id'])
                          echo "selected=selected>#$contestant[contestantno] $contestant[contestantname]</option>";
                        else
                          echo ">#$contestant[contestantno] $contestant[contestantname]</option>";
                }
              ?>
            </select>
            <input type="submit" class="buttons" value="View Score" name="cmdViewScore" id="cmdViewScore" />
            <br class="br" />
            <?php
                 $query = "SELECT id, criteria, percentage FROM subcriteria WHERE awardid=$awardid";
                $result = mysql_query($query);
                if(mysql_num_rows($result)>0)
                { 
                  echo "<table style='border: 1px solid #000; border-collapse: collapse; margin: 10px;'>";
                  echo "<tr>
                          <td style='border: 1px solid #000; background: #CCC; font-weight: bold; width: 500px; text-align: center'>Criteria</td>
                          <td style='border: 1px solid #000; background: #CCC; font-weight: bold; width: 50px; text-align: center'>Value</td>
                          <td style='border: 1px solid #000; background: #CCC; font-weight: bold; width: 50px; text-align: center'>Percentage</td>
                        </tr>";
                  while($criteria = mysql_fetch_array($result))
                  {
                    echo "<tr>";
                    echo "<td style='border: 1px solid #000; font-weight: bold;'>$criteria[criteria]</td>";
                    echo "<td style='border: 1px solid #000; text-align: center;'><input type='text' name='txtInput[]' id='txtInput[]' class='entry' size='5'". 
                          "maxLength='3' onKeyPress='return NumericEntryOnly(event)' /></td>";
                    $criteriaid[] = $criteria['id'];
                    echo "<td style='border: 1px solid #000; text-align: center;'>$criteria[percentage]%</td>";
                    echo "</tr>";
                                    
                  }
                  echo "<tr><td colspan='3'>";
                  echo "<input type='submit' name='cmdSave' id='cmdSave' value='Save' class='buttons' style='float: right;' />";
                  echo "</td></tr>";
                  echo "</table>";
                }
?>
4

As that starts with php, could you change the tags to php tags please? - Makes it a bit easier to read (it formats and colors the text differently).

Thanks.

5

That is already php…

6

Erm, no it’s using

 tags. I've just hit the quote button on your code and seen them myself :rolleyes:

PHP tags look like this 
```php
. You've not used them. I've asked you once already, I won't ask again. In case you're wondering what the fuss is about PHP tags do this and make it much easier to read:


```php

//Demonstation
$Test = 'This is a test string';

print $Test;

Also the box showing your code clearly says Code: - Not PHP Code like my demo :rolleyes: