Must "throw" be inside a try statement?

PHP
1

Hi,

I have a throw code in one of my php file which is not surrounded by the try statement like so:

File A:


function test( ) {
    if( $action ) {
        echo 1;
    }
    else {
        throw new customException( );
    }
}

File B:

include fileA.php;

try {
    test( );
}
catch( customException $e ) {
    // do something
}

Is this considered the correct way because I am stuck at this portion of code while debugging and its not showing me any error message at all. Even the error_log yields nothing.

Any help appreciated.

2

Hi justspree,

Throw is used when throwing an error inside a function or an Object’s method. The code that calls the function/method is wrapped in try/catch blocks ad if an error occurs inside the called function/method the catch part of the block runs and determines how you handle the error. Like:

 
function calculateFraction($value){
   if(!$value){
        throw new Exception('Cannot divide by zero.');
   } else {
       return (1/$value);
   }
}

/*call the function*/
try {
    echo calculateFraction(2);
    echo calculateFraction(0);
} catch (Exception $e){
    echo 'Caught exception: ',  $e->getMessage(), "\
";
}
/* Outputs */ 
 0.5 
 Caught exception: Cannot divide by zero.
?>

Steve

3

Thank you for your reply Steve. I understand that but I’m asking if is there a difference between my code and yours? Anything I’ve done wrong on mine?

4

Hi, your code is using it correctly. You may want to simplify the handling of the exception for the time being and not use a custom handler. See if you trigger an error then add your custom handler back to see if it is ‘eating’ your error.

Regards,
Steve

5

Oh ok thanks a bunch Steve! Will try it.