Sorry for bothering everyone but I have a question regarding java. (I do realize this is a java script forum but there wasn’t a forum for java so I asked here)
The question is:
Write a recursive method that print an input string in a reverse “V” shape
and then a “V” shape as below
Example:
– If the input string is “1234567” which has an odd number of characters,
then the output is:
4
3 5
2 6
1 7
2 6
3 5
4
If the input string is “abcdef” which has an even number of characters,
then the output is:
cd
b e
a f
b e
cd
I’m not sure which one to use here.
public static void printVshape (String str, int i)
public static void main(String args)
If I start with the first one,
I get to
public static void printVshape (String str, int
i)
{
if(i<0) return;
String outline;
Can someone finish of question using one of the above methods and explain why to me?
(edited to format the text in the matter in which you’re looking for - I think - Dave M)
I moved this to “Get Started” and tagged it with “general-dev”.
There will be a new category to catch all programming questions that don’t have their own category, but it’s not there yet.
here is my current output: 0 11 22 33 44* 5********5 00* 11 22*
**33
*****4
but I need:
4 3*5 26
17
17 26 3*5 4
import java.util.;
public class Diamond {
void hollow(int s) {
int i,n;
for (n = 0; n < s ; n++ ){
for (i = 0; i < s-n-1 ;i++ ){
System.out.print("“);
}
for (i = 0; i <= n; i++ ) {
if (i == 0 || i == n){
System.out.print(”" + n + "“);
}
else
System.out.print(”“);
}
System.out.println();
}
for (n = 0; n < s-1; n ++ ){
for (i = 0; i <= n ; i++ ){
System.out.print(”“);
}
for (i = 0; i < s-n-1 ;i++ ) {
if (i == 0 || i == s-n-2) {
System.out.print(”" + n + “*”);
}
else
System.out.print("");
}
System.out.println();
}
}
public static void main(String args)
{
System.out.print("Enter Size: ");
Scanner cin = new Scanner(System.in);
int num = cin.nextInt();
Diamond db = new Diamond();