Regex that will allow a 1 or 2-digit number

JavaScript
1

Hello,

Right now I use this regular expression: /^\d{2}$/

As I understand it, it will match a two digit number that begins and ends with a number, like “24”, “55”, “39” and “10”.

Right now, I’m trying to expand this to allow both 1 and 2-digit numbers that also begins and ends with a number.

So numbers like “3”, “7”, “12” and “45”.

Would I use something like /^\d{1|2}$/

Thanks

2

/^\d{1,2}$/

You separate the upper and lower bounds with a comma.

3

Unless the digits are part of a larger expression it would be easier just to check if the number is less than 100.

4

The value is part of a larger expression, so the comma for the upper and lower values works great.

Thanks both of you!

5

As I’m working through this form, I now come across a new problem.

Originally I just needed an expression that allowed for exactly only five numerical digits. This worked great /^\d{5}$/

But now, I need an expression that allows for exactly only five numerical digits OR exactly only nine numerical digits.

So now that the numbers aren’t next to each other, I don’t know what to do.

/^\d{5,9}$/ won’t work, because six, seven, or eight digit numbers just won’t work.

Thanks for any help.

6

One of theese two.


/^\\d{5}$|^\\d{9}$/

/^\\d{5}(\\d{4})?$/

I like the second myself, because I can determine which one it is by the existance of a back reference.