Show price if not null or 0.00

PHP
1

hi all

the price field is set as float

In my database there are some prices fields which have either “0.00” or “NULL” as value

i wanted to display price if the value is not “0.00” or not “NULL”


if( ($row['price'] != "0.00") || ($row['price'] != "NULL") ){
// DISPLAY PRICE
}

But the price is being shown even if its “0.00”.

Is my code correct or not ?

vineet

2

AND (&&), not OR (||).

if the price is 0.00:
if(false OR true) = true.
If the price is null
if(true OR false) = true.

3

thanks starlion

vineet

4

To be more precise, the way to logically construct the description of what you want is:

If the price is Neither “0.00” Nor Null, show price.
“Neither A Nor B” translates to logic as “Not A AND Not B”

5

“Neither A Nor B” translates to logic as “Not ( A OR B )”

:slight_smile:

6

An SQL SELECT statement returns these rows, would it be better if it did not return those rows whose price was NULL or “0.00”?

7

vinpkl, also remember that the database value NULL when retrieved by PHP becomes the PHP NULL value and not the “NULL” string. Therefore your condition as you presented will not work:

$row['price'] != "NULL"

Instead, you should write it like this:

$row['price'] !== NULL

This way you will strictly exlude NULL values.

But in PHP you can achieve your goal in a much simpler syntax because of default type casting of values:


if($row['price'] != 0) {
  // DISPLAY PRICE
}

This will display the price if it is not “0.00” or if it is not NULL, because in PHP using weak comparison (!= and ==) NULL equals 0, and string “0.00” equals 0. Only when you use strong comparison (!== or ===) then NULL does not equal 0 and string “0.00” does not equal 0.