$sql = "SELECT * FROM `extra_fields` WHERE uid = '$user'";
Is it possible to put this SELECT query into the query above?
SELECT * FROM `users` WHERE userID = '$user'
$sql = "SELECT * FROM `extra_fields` WHERE uid = '$user'";
Is it possible to put this SELECT query into the query above?
SELECT * FROM `users` WHERE userID = '$user'
yep, I did
SELECT users.*
, extra_fields.*
FROM users
LEFT OUTER
JOIN extra_fields
ON extra_fields.uid = users.userID
WHERE users.userID = '$user'
i think oddz just got the column names mixed up
Hey thanks, but it doesnt seem to work, doesnt grab any infomation from the database. If I use one of the single queries above in my first post, it will get the data fine.
SELECT
u.uid
,e.userID
,...
FROM
users u
LEFT OUTER
JOIN
extra_fields e
ON
u.uid = e.userID
WHERE
u.uid = {$user}